Nicholas Fornaciari
Wentworth Institute of Technology
Mechanical Engineering '20
Maximum Power Transfer
Part 1:
Using the Maximum Transfer Labview provided by Professor Birkett, we set V1 equal to 40mV and V2 equal to 0mV. Then we set R1 equal to 2k. The load resistor was then swept from 1k to 4k. The of doing this was to find the current and voltage that the load resistor had for the maximum power transfer.
The interface shows the maximum power transfer. Where the power is maximized with a load resistance equal to 2.2k. The voltage is equal to 21mV and the current is equal to 0.00952mA. The total power delieverd by V1 for the maximum power transfer is -0.381uW and the power absorbed by the load resistor is 21mV
Part 2:
Using the Maximum Transfer Labview provided by Professor Birkett, we set V1 equal to 5V and V2 equal to 0V. Then we set R1 equal to 680k. The load resistor was then swept from 400k to 1000k. The of doing this was to find the current and voltage that the load resistor had for the maximum power transfer.
The interface shows the maximum power transfer. Where the power is maximized with a load resistance equal to 7.15k. The voltage is equal to 2.56V and the current is equal to 3.584mA. The total power delieverd by V1 for the maximum power transfer is -17.9mW and the power absorbed by the load resistor is 2.56V